2r^2+65=3

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Solution for 2r^2+65=3 equation: 



2r^2+65=3

We move all terms to the left:

2r^2+65-(3)=0

We add all the numbers together, and all the variables

2r^2+62=0

a = 2; b = 0; c = +62;
Δ = b2-4ac
Δ = 02-4·2·62
Δ = -496
Delta is less than zero, so there is no solution for the equation

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